Two coins are tossed simultaneously. Probability of getting at least one Head is:
Two coins are tossed simultaneously. Probability of getting at least one Head is:
- $\dfrac{1}{4}$
- $\dfrac{1}{2}$
- $\dfrac{3}{4}$
- $1$
Solution
Sample space $= \{HH, HT, TH, TT\}$. At least one $H$: $\{HH, HT, TH\}$. $P = \dfrac{3}{4}$.
Asked in: IMO
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