Two coins are tossed. Probability of getting exactly one Head is:

Two coins are tossed. Probability of getting exactly one Head is:
  1. $\dfrac{1}{4}$
  2. $\dfrac{1}{2}$
  3. $\dfrac{3}{4}$
  4. $\dfrac{1}{3}$

Solution

Sample space $= \{HH, HT, TH, TT\}$. Exactly one $H$: $\{HT, TH\}$. $P = \dfrac{2}{4} = \dfrac{1}{2}$.

Asked in: IMO

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