Two coils have mutual inductance 0 . 002 H . The current changes in the first coil according to the relation…

Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i=i0sinωt, where i0=5 A and ω=50π rad s-1. The maximum value of emf in the second coil is πα V. The value of α is

Solution

The amount of flux induced in the second coil due to the first one is given by

ϕ2=Mi=Mi0sinωt   ...1

where, M is the mutual inductance of the coils.

The formula to calculate the emf induced can be written as

ε=-dϕ2dt   ...2

From equation (2), it follows that,

εmax=Mi0ω=0.002×5×50π V=π2 V

Hence, α=2.

Asked in: JEE Main 2024 (27 Jan Shift 1)

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