Two coils have a mutual inductance of $0.004 \mathrm{H}$. The current changes in the first coil according to equation $\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}$, where $\mathrm{I}_0=10 \mathrm{~A}$ and $\omega=50 \pi \mathrm{rad} \mathrm{s}^{-1}$. The maximum value of e.m.f. in the second…

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Two coils have a mutual inductance of $0.004 \mathrm{H}$. The current changes in the first coil according to equation $\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}$, where $\mathrm{I}_0=10 \mathrm{~A}$ and $\omega=50 \pi \mathrm{rad} \mathrm{s}^{-1}$. The maximum value of e.m.f. in the second coil in volt is

Aicharya · Accepted Answer

$\begin{aligned} & \left|e_sight|=M \frac{d_p}{d t} \ & \left|e_sight|=M \frac{d}{d t} I_0 \sin \omega t \ & \left|e_sight|=M I_0 \omega \cos \omega t \ 	herefore \quad & \left|e_sight|_{\max }=M I_0 \omega=0.004 	imes 10 	imes 50 \pi \ 	herefore \quad & \left|e_sight|_{\max }=(2 \pi) 	ext { volt }\end{aligned}$

Two coils have a mutual inductance of $0.004 \mathrm{H}$. The current changes in the first coil according to…

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