Two coils A and B are placed in a circuit. When current in the coil A changes by $0.8 \mathrm{~A}$ the…
Two coils A and B are placed in a circuit. When current in the coil A changes by $0.8 \mathrm{~A}$ the magnetic flux in coil $\mathrm{B}$ changes by $0.16 \mathrm{~Wb}$. The mutual inductance between the coils is
$2 \mathrm{H}$
$20 \mathrm{H}$
$0.5 \mathrm{H}$
$0.2 \mathrm{H}$
Solution
The magnetic flux in coil B is given by,
$\Phi=M i_1$
where, $M$ is the coefficient of mutual inductance, $i_1$ is the current in coil A.
$\Rightarrow M=\frac{\Phi}{i_1}=\frac{0.16 \mathrm{~Wb}}{0.8 \mathrm{~A}}=0.2 \mathrm{H}$