Two closed pipes produce 10 beats per second when emitting their fundamental nodes. If their lengths are in…
Two closed pipes produce 10 beats per second when emitting their fundamental nodes. If their lengths are in ratio of 25 : 26. Then, their fundamental frequency (in Hz) are
270, 280
260, 270
260, 250
260, 280
Solution
Here, $n_1 - n_2 = 10$ ...(i)
Using $n_1 = \frac{v}{4l_1}$ and $n_2 = \frac{v}{4l_2}$
$\implies \frac{n_1}{n_2} = \frac{l_2}{l_1} = \frac{26}{25}$ ...(ii)
On solving Eqs. (i) and (ii), we get
$n_1 = 260\text{ Hz}, n_2 = 250\text{ Hz}$