Two circular loops $\mathrm{P}$ and $\mathrm{Q}$ of radii $r$ and $n r$ respectively are made from a uniform…

Two circular loops $\mathrm{P}$ and $\mathrm{Q}$ of radii $r$ and $n r$ respectively are made from a uniform wire. Moment of inertia of $Q$ about its axis is four times that of $\mathrm{P}$ about its axis. The value of $n$ is
  1. $(2)^{\frac{2}{3}}$
  2. $(2)^{\frac{1}{3}}$
  3. $2$
  4. $\sqrt{2}$

Solution

Given, $I_Q=4 I_P$. Let $m$ be the mass per unit length of wire. $\therefore m \times 2 \pi n r(n r)^2=4\left[(m 2 \pi r) r^2\right]$ Implies $n^3=4$ $\Rightarrow n=4^{1 / 3}$

Asked in: MHT CET 2022 (06 Aug Shift 2)

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