Two circles with equal radii are intersecting at the points (0,1) and (0,-1) . The tangent at the point (0…

Two circles with equal radii are intersecting at the points (0,1) and (0,-1) . The tangent at the point (0,1) to one of the circles passes through the centre of the other circle. Then the distance between the centres of these circles is:
  1. 1
  2. 2
  3. $2 \sqrt{2}$
  4. $\sqrt{2}$

Solution

$\because$ Two circles of equal radii intersect each other orthogonally. Then $R$ is mid point of $P Q$.
and $P R=O_{1} R=O_{2} R$ $P R=\frac{1}{2} \sqrt{(0-0)^{2}+(1+1)^{2}}=1$ $\therefore$ Distance between centres $=1+1=2$.

Asked in: JEE Main 2019 (11 Jan Shift 1)

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