Two circles each of radius 5 units touch each other at the point ( 1 , 2 ) . If the equation of their common…

Two circles each of radius 5 units touch each other at the point (1,2). If the equation of their common tangent is 4x+3y=10, and C1(α,β) and C2(γ,δ),C1C2 are their centres, then |(α+β)(γ+δ)| is equal to

Solution

Let a point circle: (x-1)2+(y-2)2=0 

Equation of circle passing through the intersection of the line and the circle:C1+λL1=0

(x-1)2+(y-2)2+λ(4x+3y-10)=0
x2+y2+(2λ-1)2x+32λ-22y+5-10λ=0

r=g2+f2-c
r=(2λ-1)2+32λ-22-(5-10λ)=5
4λ2+1-4λ+94λ2+4-6λ-5+10λ=25
254λ2-25=0
λ=±2
for λ=2
x2+y2+6x+2y-15=0;C1(-3,-1)
for λ=-2
x2+y2-10x-10y+25=0;C2(5,5)
|(α+β)(γ+δ)|=40

Asked in: JEE Main 2021 (27 Aug Shift 2)

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