Two cells are connected in opposition as shown. Cell E 1 is of 8 V emf and 2 Ω internal resistance; the cell…

Two cells are connected in opposition as shown. Cell E1 is of 8 V emf and 2 Ω internal resistance; the cell E2 is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E2 is ______ V.

Solution

Current in circuit, I=8-22+4=66=1 A

Applying Kirchhoff's law from C to B,

VC-2-4×1=VB

VC-VB=6 V

Asked in: JEE Main 2024 (30 Jan Shift 1)

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