Two cars P and Q start from a point at the same time in a straight line and their positions are represented…

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by XPt=at+bt2 and XQt=ft-t2. At what time do the cars have the same velocity?
  1. a-f1+b
  2. a+f2b-1
  3. a+f21+b
  4. f-a21+b

Solution

vP=dXPdt=a+2bt
vQ=dXQdt=f-2t
Now for, vP=vQ
⇒a+2bt=f-2t
⇒2t+2bt=f-a
⇒t=f−a2(b+1)

Asked in: NEET 2016 (Phase 2)

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