Two cars of masses $m_{1}$ and $m_{2}$ are moving in circles of radii $r_{1}$ and $r_{2}$ respectively.…

Two cars of masses $m_{1}$ and $m_{2}$ are moving in circles of radii $r_{1}$ and $r_{2}$ respectively. Their speeds are such that they make complete circles in the same time $\mathrm{t}$. The ratio of their centripetal force is
  1. $\mathrm{m}_{1}: \mathrm{m}_{2}$
  2. $\mathrm{r}_{1}: \mathrm{r}_{2}$
  3. $1: 1$
  4. $\mathrm{~m}_{1} \mathrm{r}_{1}: \mathrm{m}_{2} \mathrm{r}_{2}$

Solution

Centripetal acceleration, \(a_c=\omega^{\mathbf{2}} r\) \(\begin{aligned} & \because \quad \omega=\frac{2 \pi}{T} \\ & \text {As } T_1=T_2 \Rightarrow \omega_1=\omega_2 \\ & \because \quad \frac{a_{c_1}}{a_{c_2}}=\frac{r_1}{r_2}\end{aligned}\) \(\begin{aligned} & \mathrm{F}=\mathrm{m} \times \mathrm{a} \\ & \frac{\mathrm{F}_1}{\mathrm{F}_2}=\frac{\mathrm{m}_1 \mathrm{r}_1}{\mathrm{m}_2 \mathrm{r}_2}\end{aligned}\)

Asked in: MHT CET 2020 (15 Oct Shift 2)

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