Two cars are travelling towards each other at speed of $20 \mathrm{~m} \mathrm{~s}^{-1}$ each. When the cars…
- $200 \mathrm{~m}$
- $100 \mathrm{~m}$
- $50 \mathrm{~m}$
- $25 \mathrm{~m}$
Solution
$\begin{aligned} & \left|\overrightarrow{\mathrm{u}}_{\mathrm{BA}}\right|=40 \mathrm{~m} / \mathrm{s} \\ & \left|\overrightarrow{\mathrm{a}}_{\mathrm{BA}}\right|=4 \mathrm{~m} / \mathrm{s} \\ & \text { Apply }\left(\mathrm{v}^2=\mathrm{u}^2+2 \mathrm{as}\right)_{\text {relative }} \\ & \mathrm{O}=(40)^2+2(-4)(\mathrm{S}) \\ & \mathrm{S}=200 \mathrm{~m} \\ & \text { Remaining distance }=300-200=100 \mathrm{~m}\end{aligned}$Asked in: JEE Main 2024 (09 Apr Shift 2)