Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Then the probability distribution of number of kings is

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Aicharya · Accepted Answer

here $n=2, p=\frac{4}{52}=\frac{1}{13}$ $q=\frac{48}{52}=\frac{12}{13}$ Now $P(x=0)={ }^2 C_0\left(\frac{1}{13}ight)^0 \cdot\left(\frac{12}{13}ight)^2=\frac{144}{169}$ $\begin{aligned} & P(x=1)={ }^2 C_1\left(\frac{1}{13}ight)^1 \cdot\left(\frac{12}{13}ight)^1=\frac{24}{169} \ & P(x=2)={ }^2 C_2\left(\frac{1}{13}ight)^2 \cdot\left(\frac{12}{13}ight)^0=\frac{1}{169} \end{aligned}$ Hence, option (C) is correct

Two cards are drawn successively with replacement from a well shuffled pack of 52 cards. Then the…

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