Two cards are drawn successively with replacement from a well- shuffled pack of 52. cards. Let X denote the…

Two cards are drawn successively with replacement from a well- shuffled pack of 52. cards. Let X denote the random variable of number of kings obtained in the two drawn cards. Then $\mathrm{P}(x=1)+\mathrm{P}(x=2)$ equals
  1. $\frac{49}{169}$
  2. $\frac{24}{169}$
  3. $\frac{52}{169}$
  4. $\frac{25}{169}$

Solution

Probability of getting an king card is $\frac{4}{52}$ For $\mathrm{X}=1$, the outcome of king can be either in first draw of the second draw. $\begin{aligned} & \therefore \quad \mathrm{P}(\mathrm{X}=1)=\frac{4}{52} \times \frac{48}{52}+\frac{48}{52} \times \frac{4}{52} \\ & =2 \times \frac{4}{52} \times \frac{48}{52}=\frac{24}{169} \\ & \therefore \quad \mathrm{P}(\mathrm{X}=2)=\frac{4}{52} \times \frac{4}{52}=\frac{1}{169} \\ & \therefore \quad \mathrm{P}(\mathrm{X}=1)+\mathrm{P}(\mathrm{X}=2)=\frac{24}{109}+\frac{1}{169}=\frac{25}{169} \end{aligned}$

Asked in: MHT CET 2024 (03 May Shift 2)

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