Two capillary tubes of radii $R$ and $2 R$ are dipped in water. The water rises to heights $h_1$ and $h_2$…

Two capillary tubes of radii $R$ and $2 R$ are dipped in water. The water rises to heights $h_1$ and $h_2$ respectively in the two tubes. If $m_1$ and $m_2$ be the masses of water ascended in the tubes then $m_1: m_2=$
  1. $1: 2$
  2. $1: 4$
  3. $1: \sqrt{2}$
  4. $1: 8$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

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