Two capillary tubes A and B of the same internal diameter are kept vertically in two different liquids whose densities are in the ratio $4: 3$. If the surface tensions of these two liquids are in the ratio $6: 5$, then the ratio of rise of liquid in capillary A to that in B is (assume their angles…

Question

Two capillary tubes A and B of the same internal diameter are kept vertically in two different liquids whose densities are in the ratio $4: 3$. If the surface tensions of these two liquids are in the ratio $6: 5$, then the ratio of rise of liquid in capillary A to that in B is (assume their angles of contact are nearly equal)

Aicharya · Accepted Answer

$\begin{aligned} & r_1=r_2 \ & \frac{ho_1}{ho_2}=\frac{4}{3} ; \frac{T_1}{T_2}=\frac{6}{5} ; 	heta_1=	heta_2 \ h & =\frac{2 T \cos 	heta}{r ho g} \Rightarrow h \propto \frac{T}{ho} \ \frac{h_1}{h_2} & =\frac{T_1}{T_2} 	imes \frac{ho_2}{ho_1} \ 	herefore \quad \frac{h_1}{h_2} & =\frac{6}{5} 	imes \frac{3}{4}=\frac{9}{10}\end{aligned}$

Two capillary tubes A and B of the same internal diameter are kept vertically in two different liquids whose…

Solution