Two buses P and Q start from a point at the same time and move in a straight line and their positions are…

Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by xPt=αt+βt2 and xQt=ft-t2. At what time, both the buses have same velocity ?
  1. α-f1+β
  2. α+f2β-1
  3. α+f21+β
  4. f-α21+β

Solution

As we know, v=dxdt.

Given, xPt=αt+βt2

Velocity of bus P is vP=dxPdt=α+2βt and velocity of bus Q is  vQ=f-2t

When vP=vQ

α+2βt=f-2t

 f-α=2β+1t t=f-α2β+1

Asked in: JEE Main 2022 (25 Jun Shift 2)

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