Two bodies have their moments of inertia $l$ and $2 l$ respectively about their axis of rotation. If their…

Two bodies have their moments of inertia $l$ and $2 l$ respectively about their axis of rotation. If their kinetic energies of rotation are equal, their angular momenta will be in the ratio:
  1. $2: 1$
  2. $1: 2$
  3. $\sqrt{2}: 1$
  4. $1: \sqrt{2}$

Solution

K.E. rotation $K=\frac{1}{2} I \omega^2$ Angular momenta $L=100$ $\therefore \quad K=\frac{L^2}{2}$ Here $K_1+K_2, I_1=I_1, I_2=21$ $\therefore \quad \frac{L_1}{L_2}=\sqrt{\frac{2 I_1 K_1}{2 I_2 K_2}}$ $\begin{aligned} & =\sqrt{\frac{I_1}{I_2}}=\sqrt{\frac{I}{2 I}} \\ & =\frac{1}{\sqrt{2}} \end{aligned}$

Asked in: MHT CET Full Test 7

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