Two bodies ' $A$ ' and ' $B$ ' start from the same point at the same instant and move along a straight line.…
Two bodies ' $A$ ' and ' $B$ ' start from the same point at the same instant and move along a straight line. 'A' moves with uniform acceleration ‘A’ and 'B' moves with uniform velocity (V). They meet after time ' $t$ '. value of ' $t$ ' is
$\frac{2 \mathrm{~V}}{\mathrm{a}}$
$\sqrt{\frac{V}{a}}$
$\frac{\mathrm{a}}{2 \mathrm{~V}}$
$\frac{\mathrm{V}}{2 \mathrm{a}}$
Solution
For body $\mathrm{B}$, distance travelled is $\mathrm{x}=\mathrm{Vt}$
For body $\mathrm{A}, \mathrm{x}=\frac{1}{2} \mathrm{at}^2$
$\begin{aligned}
& \Rightarrow \frac{1}{2} \mathrm{at}^2=\mathrm{Vt} \\
& \text { Or } \mathrm{t}=\frac{2 \mathrm{~V}}{\mathrm{a}}
\end{aligned}$