Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m s - 1 to the heavier block in the direction of the lighter block. The velocity of the centre of mass in m s - 1 is 2 n , then n =

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Aicharya · Accepted Answer

v CM = m 1 v 1 + m 2 v 2 m 1 + m 2 10 × 14 + 4 × 0 10 + 4 = 10 × 14 14 = 10 m s - 1 = 2 n ⇒ n = 5

Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a…

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