Two blocks A and B of masses m and 2 m are connected by a massless spring of force constant k and are placed on a smooth horizontal plane. The spring is stretched by an amount x and then released. The relative velocity of the blocks when the spring comes to its natural length is

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Aicharya · Accepted Answer

Let us assume the velocity of block A and B are v 1 and v 2 respectively. Relative velocity will be v 1 + v 2 Using conservation of linear momentum m v 1 = 2 m v 2 &#8658; &#160; &#160; &#160; v 1 = 2 v 2 Using conservation of energy 1 2 k x 2 = 1 2 m v 1 2 + 1 2 2 m v 2 2 1 2 k x 2 = 1 2 m 2 v 2 2 + m v 2 2 1 2 k x 2 = 2 m v 2 2 + m v 2 2 3 m v 2 2 = k x 2 2 v 2 2 = k x 2 6 m v 2 &#160; k 6 m . x Relative velocity = 3 v 2 = 3 k 6 m . x = &#160; 3 k 2 m . x

Two blocks A and B of masses m and 2 m are connected by a massless spring of force constant k and are placed…

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