Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. $T_1$ and $T_2$ are the total flying times of first and second ball, respectively, then the ratio of $T_1$ and…

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Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. $T_1$ and $T_2$ are the total flying times of first and second ball, respectively, then the ratio of $T_1$ and $T_2$ is :

Aicharya · Accepted Answer

$\begin{aligned} & 	ext { Given, }\left(\mathrm{H}_{\max }ight)_1=8 	imes\left(\mathrm{H}_{\max }ight)_2 \ & \frac{\mathrm{u}^2 \sin ^2 	heta_1}{2 \mathrm{~g}}=8 	imes \frac{\mathrm{u}^2 \sin ^2 	heta_2}{2 \mathrm{~g}} \ & \Rightarrow \sin 	heta_1=2 \sqrt{2} \sin 	heta_2 \ & \frac{\mathrm{~T}_1}{\mathrm{~T}_2}=\frac{2 \mathrm{u} \sin 	heta_1 / \mathrm{g}}{2 \mathrm{u} \sin 	heta_2 / \mathrm{g}}=\frac{\sin 	heta_1}{\sin 	heta_2}=2 \sqrt{2}\end{aligned}$

Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum…

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