Two balls are dropped from the top of a high tower with a time interval of \(t_{o}\) second, where \(t_{o}\)…
Two balls are dropped from the top of a high tower with a time interval of \(t_{o}\) second, where \(t_{o}\) is smaller than the time taken by the first ball to reach the floor, which is perfectly inelastic. The distance \(s\) between the two balls, plotted against the time lapse \(t\) from the instant of dropping the second ball is best represented by
Solution
Before the second ball is dropped, the first ball would have travelled some distance say \(S_{0}=\frac{1}{2} g t_{0}^{2} .\) After dropping sccond ball, relative acceleration of both balls becomes zero. So distances between them increases linearly. After some time, the first ball will collide with the ground and the distance between them will start decreasing and magnitude of relative velocity will be increasing for this time. Option (d) represents all these clearly.
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Asked in: JEE Mains - Motion In One Dimension - Chapter Test