Two angles of a quadrilateral are $60^{\circ}$ and $80^{\circ}$. The other two angles are equal. Each equals:

Two angles of a quadrilateral are $60^{\circ}$ and $80^{\circ}$. The other two angles are equal. Each equals:
  1. $100^{\circ}$
  2. $110^{\circ}$
  3. $120^{\circ}$
  4. $130^{\circ}$

Solution

Sum of remaining two $= 360 - 140 = 220^{\circ}$. Each $= 110^{\circ}$.

Asked in: IMO

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