$In ^{+3}$ (trivalent lanthanides ions) have E.C.

$In ^{+3}$ (trivalent lanthanides ions) have E.C.
  1. $[\mathrm{Xe}] 4 f^{1} \mathrm{to}(\mathrm{Xe}) 4 f^{14}$
  2. $[\mathrm{Xe}] 4 \mathrm{~d}^{1} 4 f^{\mathrm{I}}$ to $[\mathrm{Xe}] 4 \mathrm{~d}^{1} 4 f^{4}$
  3. $[\mathrm{Xe}] 4 \mathrm{~d}^{2} 4 f^{0}$ to $[\mathrm{X} \mathrm{e}] 4 \mathrm{~d}^{1} 4^{4} t^{4}$
  4. $[\mathrm{Xe}] 4 f^{\circ}$ to $[\mathrm{Xe}] 4 f^{4}$

Solution

Lanthanides have configuration of $[\mathrm{Xe}] 4 \mathrm{~F}^{1-14} 5 \mathrm{~d}^{1} 6 \mathrm{~s}^{2}$
So their trivalent ion have configuration of $[\mathrm{Xe}] 4 \mathrm{f}^{1}$ to $[\mathrm{Xe}] 4 \mathrm{~F}^{14}$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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