Total number of unpaired electrons in the complex ions $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ and $\left[\mathrm{NiCl}_4\right]^{2-}$ is $\qquad$

Question

Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{Co}^{+3}: 3 \mathrm{~d}^6 \quad \mathrm{t}_{2 \mathrm{~g}}^{2,2,2} \mathrm{e}_{\mathrm{g}}^{0,0} \ & 	ext { Unpaired e } \mathrm{e}^{-}=0 \ & \mathrm{Ni}^{+2}: 3 \mathrm{~d}^8 \quad \mathrm{e}^{2,2} \mathrm{t}_2^{2,1,1} \ & 	ext { Unpaired } \mathrm{e}^{-}=2\end{aligned}$

Total number of unpaired electrons in the complex ions…

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