Total number of geometrical isomers from the complex…
$\left[\mathrm{RhCl}(\mathrm{CO})\left(\mathrm{PPh}_{3}ight)\left(\mathrm{NH}_{3}ight)ight]$ is
- 4
- 2
- 3
- 1
Solution
The number of geometrical isomers is 3 .
Asked in: JEE-TOPICTESTS-CHEMISTRY
$\left[\mathrm{RhCl}(\mathrm{CO})\left(\mathrm{PPh}_{3}ight)\left(\mathrm{NH}_{3}ight)ight]$ is
The number of geometrical isomers is 3 .