Total number of geometrical isomers for the complex…
Total number of geometrical isomers for the complex $\left[\mathrm{RhCl}(\mathrm{CO})\left(\mathrm{PPh}_3\right)\left(\mathrm{NH}_3\right)\right]$ is
Solution
$[M(a b c d)]$ complex is square planar so will have 3 geometrical isomers.
Asked in: JEE Advanced 2010 (Paper 2)
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