Total number of antibonding electrons present in $\mathrm{O}_2$ will be
Total number of antibonding electrons present in $\mathrm{O}_2$ will be
- $6$
- $8$
- $4$
- $2$
Solution
$\begin{aligned} & \mathrm{O}_2(\sigma 1 s)^2\left(\sigma^* 1 s\right)^2(\sigma 2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma 2 p_z\right)^2\left(\pi 2 p_x^2=\pi 2 p_y^2\right) \\ & \left(\pi^* 2 p_x{ }^1=\pi^* 2 p_y^1\right)\end{aligned}$
Thus, there are total 6 electrons in antibonding orbitals
Asked in: NEET 2022 (Phase 2)
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