$\lim _{n \rightarrow…
$\lim _{n \rightarrow \infty}\left[\frac{\sqrt{n^2-1^2}}{n^2}+\frac{\sqrt{n^2-2^2}}{n^2}+\frac{\sqrt{n^2-3^2}}{n^2}+\ldots\right.$ to $n$ terms $]=$
- $\frac{\pi}{4}$
- $\frac{\pi}{2}$
- $\frac{\pi}{3}$
- $\frac{2 \pi}{3}$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2017 (24 Apr Shift 2)
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