To remove the second term of the equation $x^4-8 x^3+x^2-x+3=0$, diminish the roots of the equation by

To remove the second term of the equation $x^4-8 x^3+x^2-x+3=0$, diminish the roots of the equation by
  1. $1$
  2. $2$
  3. $3$
  4. $4$

Solution

We have, $x^4-8 x^3+x^2-x+3=0$ $ h=-\frac{\text { coefficient of } x^3}{\text { number of roots }}=\frac{-(-8)}{4}=2 $

Asked in: AP EAMCET 2002

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