To project a body of mass $m$ from earth's surface to infinity, the required kinetic energy is (assume, the radius of earth is $R_E, g=$ acceleration due to gravity on the surface of earth):

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Aicharya · Accepted Answer

$\begin{aligned} & \frac{1}{2} \mathrm{mv}_{\mathrm{e}}^2=\frac{\mathrm{GMm}}{\mathrm{R}_{\mathrm{E}}} \ & \mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}_{\mathrm{E}}^2} \ & \mathrm{~K}=\mathrm{mgR}_{\mathrm{E}}\end{aligned}$

To project a body of mass $m$ from earth's surface to infinity, the required kinetic energy is (assume, the…

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