To prepare $\mathrm{XeF}_6 \cdot \mathrm{Xe}$ and $\mathrm{F}_2$ are mixed at $573 \mathrm{~K}$ and $60-70$…
To prepare $\mathrm{XeF}_6 \cdot \mathrm{Xe}$ and $\mathrm{F}_2$ are mixed at $573 \mathrm{~K}$ and $60-70$ bar in the ratio of
- 20 : 1
- 1: 5
- 5 : 1
- 1: 20
Solution
$\underset{(1: 20)}{\mathrm{Xe}+\mathrm{F}_2} \frac{573 \mathrm{~K}}{60-70 \mathrm{bar}} \mathrm{XeF}_6$
Asked in: AP EAMCET 2017 (26 Apr Shift 1)
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