To prepare 3 -ethylpentan-3-ol, the reagents needed are:

1. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{MgBr}+\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}$
2. $\mathrm{CH}_{3} \mathrm{MgBr}+\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{3}$
3. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{MgBr}+\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{3}$
4. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{MgBr}+\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}$

Solution

First write down the structure of the required compound, observe the nature of functional group,


and review the memory for preparing the required functional group. Here the required compound is a $3^{\circ}$ alcohol having three ethyl groups, so only combination given in option $c$ will introduce three ethyl groups. ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

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