$\begin{array}{c|c|c}
A & B & Y \\
\hline 0 & 0 & 1 \\
0 & 1 & 1 \\
1 & 0 & 0 \\
1 & 1 & 1 \end{array}$
To obtain the given truth table, following logic gate should be placed at G:
$\begin{array}{c|c|c} A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array}$ To…
$\begin{array}{c|c|c}
A & B & Y \\
\hline 0 & 0 & 1 \\
0 & 1 & 1 \\
1 & 0 & 0 \\
1 & 1 & 1 \end{array}$
To obtain the given truth table, following logic gate should be placed at G:
- OR Gate
- AND Gate
- NOR Gate
- NAND Gate
Solution
For NOR gate : $\overline{\mathrm{A} \overline{\mathrm{B}}}=\overrightarrow{\mathrm{A}}+\mathrm{B}$
Asked in: JEE Main 2025 (22 Jan Shift 2)