To get an output $Y=1$ from the circuit shown below, the input must be
To get an output $Y=1$ from the circuit shown below, the input must be
(a)
(b)
(c)
(d)
Solution
$\text {Gate I is OR gate } \mathrm{Y}^{\prime}=\mathrm{A}+\mathrm{B}$
Gate II is AND gate $\mathrm{Y}=\mathrm{Y}^{\prime} \cdot \mathrm{C}$ $\therefore \mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=1$ will give $\mathrm{Y}=1$