To find the resistance of a galvanometer by the half deflection method the following circuit is used with…

To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances $\mathrm{R}_1=9970 \mathrm{~W}, \mathrm{R}_2=30 \mathrm{~W}$ and $\mathrm{R}_3=0$. The deflection in the galvanometer is d. With $\mathrm{R}_3=107 \mathrm{~W}$ the deflection changed to $\frac{d}{2}$. The galvanometer resistance is approximately:
  1. $107 \Omega$
  2. $137 \Omega$
  3. $107 / 2 \Omega$
  4. $77 \Omega$

Solution

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Asked in: JEE Main 2013 (22 Apr Online)

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