To construct $\triangle ABC$ given $BC = 5$, $\angle B = 60^{\circ}$, $AB + AC = 8$. The triangle exists…

To construct $\triangle ABC$ given $BC = 5$, $\angle B = 60^{\circ}$, $AB + AC = 8$. The triangle exists because
  1. $AB + AC = 8 > BC = 5$
  2. $AB = AC$
  3. angles are equal
  4. perimeter is $13$

Solution

Triangle inequality satisfied.

Asked in: MH-SSC-9

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