Time T , velocity C and angular momentum h are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

Question

Aicharya · Accepted Answer

M &#8733; T x C y h z M 1 L 0 T 0 = T 1 x L 1 T - 1 y M 1 L 2 T - 1 z [ M 1 &#160; L 0 T 0 ] =[ M z &#160; L y + 2 z T x - y - z ] ] &#10233; z = 1 y + 2 z = 0 , x - y - z = 0 solving y = - 2 and x = - 1 M &#8658; &#160; T - 1 &#160; C - 2 &#160; h 1

Time T , velocity C and angular momentum h are chosen as fundamental quantities instead of mass, length and…

Solution