Three resistors of 2 Ω, 3 Ω and 6 Ω are connected in (i) series, and (ii) parallel. Draw the arrangements of…
Three resistors of 2 Ω, 3 Ω and 6 Ω are connected in (i) series, and (ii) parallel. Draw the arrangements of the resistors and find the equivalent resistance of each arrangement.
Solution
(i) [circuit diagram: 2Ω, 3Ω, 6Ω resistors connected in series]
In series, Rs = R1 + R2 + R3
= (2 + 3 + 6) Ω = 11 Ω
(ii) [circuit diagram: 2Ω, 3Ω, 6Ω resistors connected in parallel]
In parallel, $\dfrac{1}{Rp}$ = $\dfrac{1}{R1}$ + $\dfrac{1}{R2}$ + $\dfrac{1}{R3}$
= 1/2 + 1/3 +1/6
= (3+2+1)/6
Rp = 1.0 Ω