Three prime numbers $p$, $q$ and $r$, each less than 20, are such that $p - q = q - r$. How many distinct…

Three prime numbers $p$, $q$ and $r$, each less than 20, are such that $p - q = q - r$. How many distinct possible values can we get for $(p + q + r)$?
  1. 4
  2. 5
  3. 6
  4. More than 6

Solution

Primes less than 20: 2, 3, 5, 7, 11, 13, 17, 19. The condition $p-q = q-r$ means $p, q, r$ form an arithmetic progression, so $p + q + r = 3q$. Three-term AP triples of primes within range: (3,5,7) sum 15, (3,7,11) sum 21, (5,11,17) sum 33, (3,11,19) sum 33, (7,13,19) sum 39. Distinct sums obtained: 15, 21, 33, 39 - giving 4 distinct values of $(p+q+r)$.

Asked in: CSAT 2025

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