Three point particles of masses 1.0   k g ,   1.5   kg and 2.5   k g are placed at three…

Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The centre of mass of the system is at a point:

  1. 0.6 cm right and 2.0 cm above 1 kg mass.
  2. 1.5 cm right and 1.2 cm above 1 kg mass.
  3. 2.0 cm right and 0.9 cm above 1 kg mass.
  4. 0.9 cm right and 2.0 cm above 1 kg mass.

Solution

Take 1 kg mass at origin

Xcm=1×0+1.5×3+2.5×05=0.9 cm
Ycm=1×0+1.5×0+2.5×45=2 cm

Asked in: JEE Main 2020 (07 Jan Shift 1)

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