Three point masses 1 . 0 kg , 1 . 5 kg and 2 . 5 kg are placed at the vertices of a right-angle triangle of sides 4 . 0 cm , 3 . 0 cm and 5 . 0 cm , as shown in the figure. The centre of mass of the system is

Question

Aicharya · Accepted Answer

Let us assume that the origin of the coordinate system is at the location of $1 kg$ mass, then

$x_{cm} = \frac{1 \times 0 + 1.5 \times 3 + 2.5 \times 0}{5} = 0.9 cm$
$y_{cm} = \frac{1 \times 0 + 1.5 \times 0 + 2.5 \times 4}{5} = 2 cm$

Three point masses 1 . 0 kg , 1 . 5 kg and 2 . 5 kg are placed at the vertices of a right-angle triangle of…

Solution