Three particles of masses 50 g , 100 g and 150 g are placed at the vertices of an equilateral triangle of…

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The x, y coordinates of the centre of mass will be:

  1. 712 m, 34 m
  2. 712 m, 38 m
  3. 34 m, 512 m
  4. 38 m, 712 m

Solution

Coordinates of A :0, 0
B:12 m,  32 m
C :(1 m, 0)
Coordinates of center of mass
xcm,ycm=50×0+150×12+100×150+150+100 m, 50×0+150×32+100×050+150+100 m
=712 m, 34 m

Asked in: JEE Main 2019 (12 Apr Shift 2)

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