Three moles of B 2 H 6 are completely reacted with methanol. The number of moles of boron containing product formed is

Question

Aicharya · Accepted Answer

B 2 H 6 + 6 C H 3 O H ⟶ 2 B O C H 3 3 + 6 H 2 For 3 moles of B 2 H 6 mole of B containing product formed = 6

Three moles of B 2 H 6 are completely reacted with methanol. The number of moles of boron containing product…