
Three infinitely long charged sheets are placed as shown in the figure. The electric force acting on a…

- $+\frac{2 \sigma q}{\varepsilon_0} \hat{\mathbf{k}}$
- $-\frac{2 \sigma q}{\varepsilon_0} \hat{\mathbf{k}}$
- $+\frac{4 \sigma q}{\varepsilon_0} \hat{\mathbf{k}}$
- $-\frac{4 \sigma q}{\varepsilon_0} \hat{\mathbf{k}}$
Solution

Given, surface charge density $=\sigma$ permittivity of the free space $=\varepsilon_0$ Now, the electric force acting on a charge $-q$ at a place the point $P$, $ \begin{aligned} & \therefore & \mathbf{F}_P & =-\frac{\sigma q}{2 \varepsilon_0} \hat{\mathbf{k}}-\frac{2 \sigma q}{2 \varepsilon_0} \hat{\mathbf{k}}-\frac{\sigma q}{2 \varepsilon_0} \hat{\mathbf{k}} \\ & \text { or } & & =-\frac{4 \sigma q}{2 \varepsilon_0} \hat{\mathbf{k}} \text { or } \mathbf{F}_p=\frac{-2 \sigma q}{\varepsilon_0} \hat{\mathbf{k}} \end{aligned} $
Asked in: AP EAMCET 2019 (20 Apr Shift 2)