Three inductances are connected as shown in figure. The equivalent inductance is

Three inductances are connected as shown in figure. The equivalent inductance is
  1. $\frac{\mathrm{L}}{4}$
  2. $\frac{5}{4} \mathrm{~L}$
  3. $\frac{7}{4} \mathrm{~L}$
  4. L

Solution

Equivalent inductance of inductances connected in parallel is $\mathrm{L}_{\mathrm{p}}=\frac{1}{\mathrm{~L}_1}+\frac{1}{\mathrm{~L}_2}$ $\therefore \quad \mathrm{L}_{\mathrm{p}}=\frac{1}{\left(\frac{2}{\mathrm{~L}}+\frac{2}{\mathrm{~L}}\right)}=\frac{\mathrm{L}}{4}$
Equivalent inductance in series $\begin{aligned} \mathrm{L}_{\mathrm{s}} & =\mathrm{L}_{\mathrm{p}}+\mathrm{L}_3 \\ & =\frac{\mathrm{L}}{4}+\frac{3}{4} \mathrm{~L}=\mathrm{L} \end{aligned}$ *

Asked in: MHT CET 2024 (03 May Shift 1)

Practice more Electromagnetic Induction questions on Aicharya