
Three inductances are connected as shown in figure. The equivalent inductance is

- $\frac{\mathrm{L}}{4}$
- $\frac{5}{4} \mathrm{~L}$
- $\frac{7}{4} \mathrm{~L}$
- L
Solution
Equivalent inductance in series $\begin{aligned} \mathrm{L}_{\mathrm{s}} & =\mathrm{L}_{\mathrm{p}}+\mathrm{L}_3 \\ & =\frac{\mathrm{L}}{4}+\frac{3}{4} \mathrm{~L}=\mathrm{L} \end{aligned}$ *
Asked in: MHT CET 2024 (03 May Shift 1)
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