Three immiscible transparent liquids with uniform refractive indices $\frac{3}{2}, \frac{4}{3}$ and $\frac{6}{5}$ are arranged one on top of another. The depths of the liquids are 3 cm 4 cm and 6 cm respectively. The apparent depth of the vessel is

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Aicharya · Accepted Answer

$\mu=\frac{	ext { Real depth }(R)}{	ext { Apparent depth }} \Rightarrow 	ext { Apparent depth }=\frac{R}{\mu}$ For vessel, $\begin{aligned} 	ext { Apparent depth } & =\frac{R_1}{\mu_1}+\frac{R_2}{\mu_2}+\frac{R_3}{\mu_3} \ & =\frac{3}{3 / 2}+\frac{4}{4 / 3}+\frac{6}{6 / 5} \ & =2+3+5 \ 	ext { Apparent depth } & =10 \mathrm{~cm} \end{aligned}$ /

Three immiscible transparent liquids with uniform refractive indices $\frac{3}{2}, \frac{4}{3}$ and…

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