Three forces F 1 = 10   N ,   F 2 = 8   N ,   F 3 = 6   N are acting on a particle…

Three forces F1=10 N, F2=8 N, F3=6 N are acting on a particle of mass 5 kg. The forces F2 and F3 are applied perpendicularly so that particle remains at rest. If the force F1 is removed, then the acceleration of the particle is

  1. 7 m s2
  2. 0.5 m s2
  3. 4.8 m s2
  4. 2 m s2

Solution

When the force F1 is removed, the particle starts accelerating because of the resultant force between F2 and F3.

The resultant force can be calculated as follows:

F=F22+F32=10 N

Hence, the acceleration of the particle is given by

a=10 N5 kg=2 m s2

Asked in: JEE Main 2023 (12 Apr Shift 1)

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